| A
four point supported glass pane 1600x1000mm shall be
calculated. This pane is horizontally arranged and
only loaded by face loads (or other loads as point
loads in the middle of the pane). The point fixings
are all located 100x100mm from the corner.
So, instead of
generating the total system, only one quarter can be
consider - as we know that the other 3 quarters acts identically
in the same way as the one simulated (left as right
and bottom as the top half)
For this, the system
must now be halved at the symmetry lines
and the two new
boundary conditions must be adjusted to this local
situation.
The border 2 now will get the "typ 2"
boundary and border 3 the "typ 3" form the
predefined settings:
This will set the conditions that for example in
x-direction no deformation (u) can arise and that the
rotation (phi) here equals zero.
When doing so for insulated glass units, you have to
take care that those symmetry borders don't get spacers! Those borders are
located within the pane and not
at the sealed outside.
For this example, instead of 5900 unknown to solve, now only 1400 d.o.f.
must be regarded. But the resulting stresses and
deformations are equal.
|
Front view
symmetrically deformed
one quarter with
corresponding boundary conditions at the symmetry
lines
|
